g(x)周期为1，因此有g(x+1)=g(x)
f(x+1)=(x+1)+g(x+1)
=x+g(x)+1
=f(x)+1
同理，
f(x+2)=f(x+1)+1
=>f(x+2)=f(x)+2
当0<=x<=1时，-2<=f(x)<=5
=>-1<=f(x)+1<=6
=>-1<=f(x+1)<=6 ,则1<=x<=2时，-1<=f(x)<=6
=>0<=f(x+2)<=7,则2<=x<=3时，0<=f(x)<=7
因此有0<=x<=3时，-2<=f(x)<=7
所以f(x)的值域是[-2,7]
1题B 2题D 3题 向左平移1/2个单位得到y=2x 1,向右平移1/2个单位得到y=2x-1 4题 设y=kx b,将（34,22）（40,25）两点代入方程得k=1/2,b
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