数学分式化简……要具体步骤

ac·(√2+√6)/8=3+√3 ,ac是一个常数……,求ac?
2025-05-07 03:22:02
推荐回答(3个)
回答1:

ac·(√2+√6)/8=3+√3
ac=(3+√3)x8/(√2+√6)
ac=(3+√3))(√6-√2)x8/(√2+√6)(√6-√2)
ac=(3+√3))(√6-√2)x8/4
ac=(3√6-3√2+3√2-√6)x8/4
ac=2√6x2
ac=4√6

回答2:

ac·(√2+√6)/8=3+√3
ac=(3+√3)/(√2+√6)/8
ac=8(3+√3)/(√2+√6)
=8(3+√3))(√2-√6)/-4
=-2(3√2+√6-3√6-3√2)
=4√6

回答3:

不懂